2h^2+14h-112=0

Solution for 2h^2+14h-112=0 equation:

2h^2+14h-112=0

a = 2; b = 14; c = -112;
Δ = b2-4ac
Δ = 142-4·2·(-112)
Δ = 1092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1092}=\sqrt{4*273}=\sqrt{4}*\sqrt{273}=2\sqrt{273}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{273}}{2*2}=\frac{-14-2\sqrt{273}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{273}}{2*2}=\frac{-14+2\sqrt{273}}{4}
$